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Port Jefferson is a village in Salem Township, Shelby County, Ohio, United States. The population was 321 at the 2000 census.
GeographyPort Jefferson is located at (40.330423, -84.090979)[3]. According to the United States Census Bureau, the village has a total area of 0.2 square miles (0.4 km²), all of it land. DemographicsAs of the census[2] of 2000, there were 321 people, 122 households, and 90 families residing in the village. The population density was 2,084.8 people per square mile (826.3/km²). There were 128 housing units at an average density of 831.3/sq mi (329.5/km²). The racial makeup of the village was 99.69% White and 0.31% Asian. There were 122 households out of which 29.5% had children under the age of 18 living with them, 58.2% were married couples living together, 9.8% had a female householder with no husband present, and 26.2% were non-families. 22.1% of all households were made up of individuals and 6.6% had someone living alone who was 65 years of age or older. The average household size was 2.63 and the average family size was 2.97. In the village the population was spread out with 22.7% under the age of 18, 9.0% from 18 to 24, 34.6% from 25 to 44, 19.0% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 103.2 males. For every 100 females age 18 and over, there were 108.4 males. The median income for a household in the village was $34,306, and the median income for a family was $47,000. Males had a median income of $31,063 versus $21,154 for females. The per capita income for the village was $16,897. About 5.0% of families and 8.3% of the population were below the poverty line, including none of those under age 18 and 18.4% of those age 65 or over. Miami and Erie CanalThe northern end of the Port Jefferson or Sidney feeder of the Miami and Erie Canal was located just north of Port Jefferson. There are stone ruins left in the river. References
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