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Troy is a city in Madison County, Illinois, United States. The population was 8,524 at the 2000 census.
GeographyTroy is located at (38.729236, -89.891733).[1] According to the United States Census Bureau, the city has a total area of 4.2 square miles (10.8 km²), all of it land. DemographicsAs of the census[2] of 2000, there were 8,524 people, 3,100 households, and 2,356 families residing in the city. The population density was 2,037.6 people per square mile (787.4/km²). There were 3,201 housing units at an average density of 765.2/sq mi (295.7/km²). The racial makeup of the city was 95.48% White, 1.48% African American, 0.32% Native American, 0.70% Asian, 0.38% from other races, and 1.64% from two or more races. Hispanic or Latino of any race were 1.49% of the population. A special census in 2007, however, showed that the population had grown to 10,083, according to news coverage from the Belleville News-Democrat. There were 3,100 households out of which 45.2% had children under the age of 18 living with them, 60.1% were married couples living together, 12.5% had a female householder with no husband present, and 24.0% were non-families. 19.5% of all households were made up of individuals and 6.8% had someone living alone who was 65 years of age or older. The average household size was 2.75 and the average family size was 3.16. In the city the population was spread out with 30.2% under the age of 18, 8.6% from 18 to 24, 34.3% from 25 to 44, 19.2% from 45 to 64, and 7.7% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 96.0 males. For every 100 females age 18 and over, there were 91.5 males. The median income for a household in the city was $53,720, and the median income for a family was $59,643. Males had a median income of $41,705 versus $27,542 for females. The per capita income for the city was $21,174. About 2.1% of families and 3.4% of the population were below the poverty line, including 3.4% of those under age 18 and 4.5% of those age 65 or over. References
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