Florida Bay Harbor Islands
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Bay Harbor Islands is a town in Miami-Dade County, Florida, United States. The population was 5,146 at the 2000 census.
HistoryIt was founded by Shepard Broad in April of 1947. GeographyBay Harbor Islands is located at (25.887522, -80.135739).[3] It consists of two islands. The west island contains exclusively single family homes and the east island contains a business district and multi-family housing. According to the United States Census Bureau, the town has a total area of 1.6 km² (0.6 mi²). 1.0 km² (0.4 mi²) of it is land and 0.6 km² (0.2 mi²) of it (39.34%) is water. DemographicsAs of the census[1] of 2000, there were 5,146 people, 2,612 households, and 1,295 families residing in the town. The population density was 5,370.0/km² (13,875.4/mi²). There were 3,103 housing units at an average density of 3,238.0/km² (8,366.8/mi²). The racial makeup of the town is 91.22% White (60.1% were Non-Hispanic White,)[4] 1.79% African American, 0.08% Native American, 1.22% Asian, 0.06% Pacific Islander, 2.84% from other races, and 2.80% from two or more races. 35.29% of the population are Hispanic or Latino of any race. There were 2,612 households out of which 20.3% had children under the age of 18 living with them, 35.6% were married couples living together, 10.7% had a female householder with no husband present, and 50.4% were non-families. 43.1% of all households were made up of individuals and 18.6% had someone living alone who was 65 years of age or older. The average household size was 1.97 and the average family size was 2.71. In the town the population was spread out with 18.0% under the age of 18, 5.0% from 18 to 24, 32.1% from 25 to 44, 21.7% from 45 to 64, and 23.3% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 80.1 males. For every 100 females age 18 and over, there were 75.3 males. The median income for a household in the town was $38,514, and the median income for a family was $43,939. Males had a median income of $38,750 versus $31,044 for females. The per capita income for the town was $29,261. About 8.0% of families and 13.1% of the population were below the poverty line, including 20.7% of those under age 18 and 6.8% of those age 65 or over. As of 2000, speakers of English as a first language consisted of 52.04%, while Spanish accounted for 43.90%, Portuguese was at 1.65%, Hebrew at 1.29%, and French made up 1.10% of the population.[5] As of 2000, Bay Harbor Islands had the twenty-second highest percentage of Colombian residents in the US, with 4.72% of the US populace.[6] It had the fifty-first highest percentage of Cuban residents in the US, at 8.51% of the town's population.[7] It also had the ninth most Peruvians in the US, at 3.11%,[8] while it had the twentieth highest percentage of Romanians, at 1.10% of all residents (tied with Hollywood, Florida and many other areas in the US.)[9] Bay Harbor Islands' Turkish community had the seventh highest percentage of residents, which was at 1.20% (tying with five other US areas, such as Highland Beach.)[10] It's also home to the seventeenth highest percentage of Venezuelan residents in the US, at 1.15% of the population.[11] References
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